posted by tia .
What is the pH of the solution created by combining 12.00 mL of the 0.10 M base with 8.00 mL of the 0.10 M acid
correction: the base is NaOH and acid is HC2H3O2
I'll let HAc stand for HC2H3O2.
Then NaOH + HAc ==> NaAc + H2O.
Calculate mols NaOH. mols = L x M = ??
Calculate mols HAc. mol = L x M = ??
They react in 1:1 ratio. Use logic to determine how much NaAc is produced and how much NaOH remains unreacted. Note: Check the problem. Problems of this type USUALLY have excess acid, not base, so it makes a buffer solution. This one is not a buffer.