Algebra
posted by John .
min/max point
minimum or maximum
f(x)=2x^2+8x2
a=2
x=(b)/(2a)=(8)/(2)(2)=4
x=4
y=2(4)^2+8(4)2
2(16)322
32322
y=2
(4,2)
axis of symmetry is x=4
range[2,oo]
minimum value 2

I think you messed up when trying to find the axis of symmetry. There's a small calculation error there and it seems to have thrown off all your answers. However, your work overall is correct.

when you used the calculator to find (8)/(2)(2) you did not consider the order of operations you must multiply 2 by 2 before you divide 8 by the answer, otherwise your method is correct

My range changes to 10 and the axis is x=2, and min value is 10?

Yes.