physics
posted by Jon .
A player kicks a football with an initial velocity of 3.00 m/s at an angle of 60.0 above the horizontal. What is the horizontal distance traveled by the football?
2(3.00)(cos60)/9.80
(3.00)(cos60)(.530219635)
0.795m

The looks like a pretty short punt to me: about 2 feet. The correct formula is (horizontal velocity component)* (time of flight). There should be a sin 60 and a v^2 in the answer, besides the factors already there in your first equation.
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