precalc
posted by Devon .
A ship travels 200km west from port and then 240km due south before it is disabled. Illustrate this in a vector diagram. Usa trigonometry to find the course that a rescue ship must take from port in order to reach the disabled ship.
i don't know where to begin, could someone just help know where to start?

Draw an xy graph with the port at the origin (x=0, y=0) Let up (+y) be north and right (+x) be east. After going west the ship is at (200, 0), which means x=200, y=0. Draw the line that it travelled as an arrow from the origin to that point. Then draw another arrow for the next part of its journey, from (200,0) to (200,240)..The course that a rescue ship must take is from (0,0) to (200,240)
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