Algebra II
posted by Lucy .
Use log5(2)=0.4307 and log5(3)=0.6826 to approximate the value of log5=54.
According to the example in my book I would divide 0.6826 by 0.4307 and the answer is 1.5848 but this is not one of the answers given.
My choices are:
a) 0.1370
b) 2.4785
c) 0.8820
d) 0.7488
Where did I go wrong?
Thanks

54 = 2*3*3*3
log 54 = log 2 + 3 log 3
= .4307 + 3(.6826)
= 2.4785
Well, at least I agree with one of them ! 
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