Algebra II

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I cannot figure out how to work this one. I have tried working it like the example in the book but cannot come up with one of the answers given. Please help.

Use log5(2)=0.4307 and log5(3)=0.6826 to approximate the value of log5=54.

According to the book's example you would divide 0.6826 by 0.4307 which equals 1.58 (not one of the choices)

a) 0.1370
b) 2.4785
c) 0.8820
d) 0.7488

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