Algebra

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A big sale is happening today at the Newton Shoe Store. You buy two pair od running shoes. The first pair is \$64, which is 20% off the original price. The second pair os \$72, which is 40% off the original price. what is the persent of discount on the Combined purchase os the two pairs of shoes? (assuming no sales tax is involved)

I know that you have to find the original prices of the shoes, then, add that together, then add the percents together, and find the total percent, correct?
I don't know how to get to the original price, or how to find the end percent. Can anyone help?
Thanks!

• Algebra -

To find the original price:

Since the price for the first pair is 20% off the original price, you're actually paying 80% of the original price.

0.8x = 64
x = 64/0.8
x = 80

Using the same method, find the original price of the second pair.

• Algebra -

would the second pair be \$120?

then you add those together, and that equals \$200.

Here's were I'm stuck.
Would you make the \$200 a percent then subtract it by the sum of the 80% and 60%? your answer would be 50%.

• Algebra -

Yes. The original price of the second pair was \$120 -- so the two pairs of shoes together would have cost \$200.

But you paid only paid \$136 for the twopairs.

To find the percent of discount for both pairs:

\$200 - 136 = \$64

64/200 = .32 = 32%

• Algebra -

Oh THANK YOU!!! i've benn so confused!

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