Adiabatic rates(Geography)
posted by Sarah .
Given a lapse rate of 3 degrees C/1000 meters and a temp of 20 degrees C at 0 meters:
A.What is the air sitting at 3,000 meters elevation?___degrees C
B.If a sample of air were lifted from 0 meters to 3,000 meters elevation, what would its new temp be?_____C(Assume no condensation is occuring.)
I don't undertsnad how to figure this out at all....

Adiabatic rates(Geography) 
Damon
A, 20  3 (3000/1000)
=20  9
= 11 deg C
B. if it really is "adiabatic",no heat lost or gained by gas during drop in pressure.
for an ideal gas with g =1.4
Po Vo^g = P V^g
To * Vo^(g1) = T * V^(g1)
for atmosphere the pressure is approximately
P = Po e^(M G/R T)y
at 3000 meters using T =293:
M = mol mass of air = 28.8 *10^3 kg/mol
G = 9.8 m/s^2 gravity
R = 8.315 J/mol deg K gas constant
so
ln (P/1 atm) = .347
P = .706 atm
so what is the volume ratio V/Vo of a mol for example ?
(V/Vo)^1.4 = =Po/P = 1/.706 = 1.42
1.4 ln (V/Vo) = 1.416
ln V/Vo = 1.01 expands
V/Vo = 2.75 expansion ratio
so what is T actually?
To * Vo^(g1) = T * V^(g1)
T = To (Vo/V)^(g1) with g = 1.4
T = 293 (.364)^.4
ln (T/293) = .4 ln (.364)
ln (T/293) = .4245
T = 293(.654)
T = 192 K
= 81 C
CHECK MY ARITHMETIC !!! 
First arithmetic fix 
Damon
so what is the volume ratio V/Vo of a mol for example ?
(V/Vo)^1.4 = =Po/P = 1/.706 = 1.42
1.4 ln (V/Vo) = .3507
ln V/Vo = .25046 expands
V/Vo = 1.28 expansion ratio
Vo/V = .778
so what is T actually?
To * Vo^(g1) = T * V^(g1)
T = To (Vo/V)^(g1) with g = 1.4
T = 293 (.778)^.4
ln (T/293) = .4 ln (.778)
ln (T/293) = .1004
T = 293(.904)
T = 265 K
= 8 C
CHECK MY ARITHMETIC !!! 
Adiabatic rates(Geography) 
no name
The way I would do it is as follows:
You gave a lapse rate of 3ºC per 1000m
Air cools the higher you get (to a certain point, but that doesn't interest us for this example)
If the air at 0 is 20ºC and it cools by 3º every 1000m  then the air at 3000m
is 9ºC cooler  namely 11ºC
20  9 = 11ºC
________________________________________
Problem B; you didn't give a lapse rate for this example, so I am assuming that you are supposed to use the correct dry adiabatic lapse rate which is:
10ºC for 1000m (or 5.5ºF per 1000')
Thus, assuming that the temp. at 0 is still 20ºC the air at 3000m would be 30ºC cooler (3x10) namely 10ºC
20  30 = 10ºC
At least, that's the way I would do it.
(Actually, the normal lapse rate is 3.5ºF per 1000' or 6.4ºC for 1000m)
The wet adiabatic rate is 3.3ºF per 1000' or 6ºC per 1000m
FALLING air always WARMS at the DRY adiabatic rate
Respond to this Question
Similar Questions

Geog
2 at sea level the air temperature is 80 degree F. this air reaches the dewpoint at 6,000’. The air continues to rise, pushed up by trade winds, over a mountain that is 12,000’ high. If the dry adiabatic rate is 5.5 degree F/ … 
GeogAdiabatic rates
Given a lapse rate of 3 degrees C/1000 meters and a temp of 20 degrees C at 0 meters: A.What is the air sitting at 3,000 meters elevation? 
Science HELP!!
LCL is the height where air has cooled to the dew point. We can calculate LCL using temperature and dew point at the surface. Like temperature dew point also decreases with height because of decreasing pressure. Dew point drops at … 
Melanie
A right triangle has a hypotenuse of length 13 meters and one side of length 5 meters. What is the length of the third side and the angle between the hypotenuse and the 5 meter side? 
physics
A ball is released from a hot air balloon moving downward with a velocity of 10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? 
physics
A ball is released from a hot air balloon moving downward with a velocity of 10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? 
physics
A ball is released from a hot air balloon moving downward with a velocity of 10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? 
physics
A ball is released from a hot air balloon moving downward with a velocity of 10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? 
Science
An air mass of 25°C with a dew point of 10°C has a starting elevation of sea level (0 meters) encounters a mountain range with a peak elevation of 3,000 meters above sea level. At what elevation is the Lifting Cloud Level? 
Geography
Why are map's elevation scales often given in feet and meters?