Algebra Problem
posted by Jim .
State the value of the discriminant and the number of real solutions.
t^2+14t+49=0
The value of the discriminant is 0 and the equation has no real solution.

No
If the discriminant is zero, then the quadratic factors to a perfect square, and there will be one real solution (actually two real but equal solutions)
t^2+14t+49=0
(t+7)^2 = 0
t+7 = 0
t = 7