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alg

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i need help solving this one (x + 4)^2/3= 9 a) 13 b) 23;-31 c) 5 d) 31;-31

also sove check for extraneous solutions
(6x-5)^1/2 = (7+ 4x)^1/2
a) 1/6 b) -9 c) 6 or d) 1/5

  • alg -

    (x+4)^1/3 = 3 or -3
    (x+4) = 27 or -27
    x = 23 or -31

    ================
    For your other one, square both sides:
    6x -5 = 7 + 4x
    2x = 12
    x = 6

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