alg
posted by John .
i need help solving this one (x + 4)^2/3= 9 a) 13 b) 23;31 c) 5 d) 31;31
also sove check for extraneous solutions
(6x5)^1/2 = (7+ 4x)^1/2
a) 1/6 b) 9 c) 6 or d) 1/5

(x + 4)^2/3= 9
[(x + 4)^2/3]^(3/2)= 9^(3/2)
x+4 = 27
x = 23
do the second one by squaring both sides 
ok so for this one i need help solving this one (x + 4)^2/3= 9 a) 13 b) 23;31 c) 5 d) 31;31
it would be c 23 or 31 right?
for for the 2nd one i got 9?
but i don't think i did it right