the base of the pyramid of Khufu is a
square with side 230m long. calculate
the length of the diagonal of this square. too
the nearest tenth of a meter.
please Explain your answer...
D^2 = 230^2 + 230^2
D^2 = 105800
D = √105800 = 325.26
So to the nearest metre it is 325 m long
To calculate the length of the diagonal of a square, you can use the Pythagorean theorem. The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the square represents the base of the pyramid of Khufu, which is a square with a side length of 230 meters. We need to find the length of the diagonal, which is the hypotenuse of a right-angled triangle.
Since the square is a right-angled shape, we can draw two right-angled triangles by drawing diagonals across the square. Each right-angled triangle will have two sides equal to 230 meters (the length of the square's side) and a hypotenuse (the diagonal) that we want to calculate.
Using the Pythagorean theorem, we can find the length of the diagonal (D) as follows:
D^2 = 230^2 + 230^2
Simplifying this equation:
D^2 = 52,900 + 52,900
D^2 = 105,800
Taking the square root of both sides of the equation:
D = √105,800 ≈ 325.16 meters
Therefore, the length of the diagonal of the square base of the pyramid of Khufu is approximately 325.16 meters when rounded to the nearest tenth.