Algebra
posted by Tim .
Can someone tell me if I am right?
Factor by group
20x^212x=15x9
20x^2+3x+9
(4x+3)(5x3) answer

20x^227x9

meant +9 and then do the rest.

yes, you are right, but you should have maintained your equation.
20x^2+3x+9 = 0
(4x+3)(5x3) = 0
You could have tested your answer by expanding it to get back the
20x^2+3x+9 = 0 
oops, just looked at your second line and assumed you would have had that one correct,
Chad is correct above. 
So my second line should be:
20x^227x+9=0 
yes, and it factors to
(5x3)(4x3) = 0
test the answer by expanding it 
Sorry, I put and = when it should have been a +! Is the one below right?
20x^212x+15x9
20x^212x+15x9
= 20x^2+3x9
= (4x+3)(5x3)