WHAT IS THE PERCENT MASS OF SODIUM HYDROXIDE IF 2.5G OF naoh ARE ADDED TO 50.00G OF H20?
THE ANSWER IS:
4.76%
explanation: you have to add the 2.5 grams with the 50 grams to get 52.5g, then you take the 2.5 gram of NaOH which is what they ask you to find the percent mass of, and (2.5grams/52.5grams) x 100
the resulting answer should be 4.76%
this is called percent by mass
To calculate the percent mass of sodium hydroxide (NaOH) in the given solution, you need to use the formula:
Percent Mass = (Mass of NaOH / Total Mass of Solution) x 100
First, determine the mass of NaOH by subtracting the mass of water from the total mass of the solution:
Mass of NaOH = Total Mass of Solution - Mass of H2O
Given:
Mass of NaOH = 2.5g
Mass of H2O = 50.00g
Total Mass of Solution = Mass of NaOH + Mass of H2O
Substituting the values:
Total Mass of Solution = 2.5g + 50.00g = 52.5g
Now, substitute the values into the percent mass formula:
Percent Mass = (2.5g / 52.5g) x 100
Calculating:
Percent Mass = 0.0476 x 100
Rounding to the appropriate number of significant figures:
Percent Mass = 4.8%
Therefore, the percent mass of sodium hydroxide in the solution is 4.8%.