An automatic drier spins wet clothes at an angular speed of 4.8 rad/s. Starting from rest, the drier reaches its operating speed with an average angular acceleration of 3.6 rad/s2. How long does it take the drier to come up to speed?
someone confirm this;
a)ω =(65rev/min)*1min/60sec*2πrads/1rev=65 π rads/30sec b) ω0=0 c) α=7rad/s^2
Hence, t= (ω- ω0)/α
To find the time it takes for the drier to come up to speed, we can use the formula:
ω = ω₀ + αt
Where:
- ω is the final angular speed (4.8 rad/s)
- ω₀ is the initial angular speed (0 rad/s, as it starts from rest)
- α is the average angular acceleration (3.6 rad/s²)
- t is the time we are trying to find
We can rearrange the formula to solve for t:
t = (ω - ω₀) / α
Substituting the given values, we get:
t = (4.8 rad/s - 0 rad/s) / 3.6 rad/s²
t = 1.33 seconds
Therefore, it takes the drier approximately 1.33 seconds to come up to speed.