Algebra
posted by Jon .
During a clothing sale, 1/4 of the store merchandise is reduced in price. Find the probablility that 3 of 5 randomlyselectled shirts have reduced prices.

Probability all 5 are reduced is
P(5) = (1/4)^5 = 0.000996
Probability that none are reduced is
P(0) = (3/4)^5 = 0.3773
Probability that 3 out of 5 are reduced is
P(3) = (1/4)^3*(3/4)^2* [5!/(2!*3!]= 0.0879
P(1) = (1/4)(3/4)^4*5 = 0.3955
P(2) = (1/4)^2*(3/4)^3*[5!/(2!*3!)] = 0.2637
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