physics again...
posted by rory .
A 62.0 kg diver falls from rest into a swimming pool from a height of 3.50 m. It takes 1.92 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.

First, calculate the velocity when he hits the water using:
V(f)^2 = V(o)^2 + 2as
Then, calculate the deceleration as he goes through the water using:
V(f) = V(o) + at.
Then you can get the force once you know a with F = ma. 
they want us to use the height somehow.

yes, in my first equation, the "s" is distance, or in this case, height.

yeah its still not working i did that i think it wants us to more of an kinetic energy or work method to solve for it.

OK, you can do it that way. First, he has potential energy = mgh. This gets converted into kinetic energy. The kinetic energy when he hits the water is (mv^2)/2, so you can calculate his velocity when he hits the water. Then calculate his deceleration, and the force.

thanks!

you're welcome!
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