Post a New Question

calculus

posted by .

determine whether the series converges of diverges

the sum from k=1 to infinity of

sin(e^-k)

I'm not sure where to start..

  • calculus -

    As k becomes large, e^-k becomes much less than 1, and sin(e^-k) approaches e^-k
    The sum of the series 1 + 1/e + 1/e^2 converges to
    1 /(1 - 1/e)= 1.582
    High-order terms of the series
    sin(e^-k) will behave similarly, but the sum of the entire series will be somethat less than 1.582.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question