# calculus

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determine whether the series converges of diverges

the sum from n=1 to infinity of

1/(the square root of (n^3+1))

I said that through the comparision test (comparing to 1/the square root of (n^3) the series converges
is this true?

• calculus -

That is a valid way to do it. Yes, every term is smaller than 1/n^3

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