Chemistry
posted by Kelsey .
How would you prepare 1.00L of 0.13m solution of sugar, C12H22O11? The density of the resulting solution is 1.10g/mL.
m=molality

Use mass = volume x density to calculate the mass of 1000 mL of the final solution. Then use the definition of molality = mols/kg solution.
I like to calculate the mass, then put molality into a single equation, which is,
kg x m x molar mass = grams.
You know kg, m, and molar mass. Calculate grams.
Post your work if you get stuck or don't understand what I've done. 
I don't undastnd.
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