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A 0.052-kg arrow is fired horizontally. The bowstring exerts an average force of 80 N on the arrow over a distance of 0.75 m.

With what speed does the arrow leave the bow?

  • physics -

    The average force multiplied by the 0.75 m distance is the work done on the arrow, and equals the kinetic energy of the arrow when it leaves the bow.

    Therefore 80 x 0.75 = 60 J = (1/2) m V^2

    You know what the arrow's mass (m) is; so solve for V

  • physics -

    10.95 m/s

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