Math
posted by Jon .
1)Solve 3+2(1x)>6 or 2x+14<=8. Graph the solution set on a number line.
The number line I'm working with is:
4 3 2 1 0 1
First solution:
3+22x>6
52x>6
2x>1
x> 1/2
for the graph, I have an open circle between 0 and 1 and the arrow going right.
Second solution:
2x+14<=8
2x<= 6
x<= 3
for the graph, I have a closed circle on the 3 and the arrow going left.

seem right to me.

You made an error in the first part.
for the first one you had
2x>1
x> 1/2
when you divide by a negative, the inequality sign has to be reversed, so it is
x < 1/2
so that would be an open circle at 1/2 and the line going to the left.
since your relations are joined with OR and the second one is x < 3
the actual solution would be the first graph above.
Respond to this Question
Similar Questions

Math
The graph of the equation y=4x consists of all the points in the coordinate plane that satisfy the equation. List 5 points that satisfy y= 4x. Also, what do you think is the minimum number of points you need to plot in order to draw … 
Algebra II
I need some help with some problems as well as need some checked. Could you please help me? 
Math inequalitites
Hi, I need some help with some inequalitites. Thanks!! Use graphs to find the set. 1.(9,0) intersection [4,] I got [4,0) 2. (9,0) U [4,10] I got (9,10] Solve the linear inequality. Other than (empty set, use interval notation … 
Algebra II
Solve: 3+2(1x) >6 or 2x+14 <=8. Graph the solution set on a number line. When I solved the equations for the first one I got x<1/2 and for the second one I got x<= 3. How do I graph the solution set for these? 
Math
( / means absolute value) Solve: 3+/2y1/>=1. Graph the solution set on a number line. The number line I have is: 5 4 3 2 1 0 1 2 3 4 5 6 First solution: 3+2y1>=1 2y4>=1 2y>=5 y>=5/2 I'm stuck b/c I had to correct … 
Math
( / means absolute value) Solve: 3+/2y1/>=1. Graph the solution set on a number line. The number line I have is: 5 4 3 2 1 0 1 2 3 4 5 6 I'm confused on what to do. 
Math
Solve and graph the solution set on a number line. 5x + 7  2 < 4 <> 5 4 3 2 1 0 1 2 3 4 
college algebra
1. find the equation of the line with the given properties. Express the equation in general form or slopeintercept form. perpendicular to the line 3x_y= 27; contains the point (9, 1) the equation of the line is ? 
math
solve the polynomial inequality and graph the solution set on a real number line. express the solution set in interval notation x^3+x^2+64x+64>0 show work please 
math
Consider these two tables for Line 1 and Line 2. Line 1: x  y 0 1 3 4 Line 2: x  y 0 0 2 4 (a) Graph Line 1 (already did this) (b) Graph Line 2 on the same graph (already did this) (c) What is the solution to the system?