posted by shan .
600g of water is mixed with 20g of steam at 100 deg Celcius. What is the final temperature if the original temperature of the water is 25 deg Celcius
The 20 g of steam will transfer 20g*540 Cal/g of heat to the liquid water while condensing. That makes 10,800 Cal, which is enough to raise the liquid water temperature by 18 C, to 38 C. As a final step, calculate the equilbrium temp T when mixing 600g liquid H2O at 38 C with 20 g of liquid H2O at at 100 C.
600(T - 38) = 20(100 - T)
Solve for T