calculus
posted by anonymous .
Find the total distance traveled by the particle moving along a straight line with velocity v=sinpit for 0<t<2.

Distance travelled = integral of V dt
= Integral of sin (pi*t) dt
t = 0 to 2
=  cos(2) + cos(0) = 1  cos(2) = 0.58385
Respond to this Question
Similar Questions

Calculus
A particle moves in a straight line with velocity t^2  1/9 ft/s. Find the total displacement and total distance traveled over the time interval [1,4]. I found out that the total displacement is .4116 But I cannot find the total distance … 
math
The velocity function is v(t) = t^2  6 t + 8 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [1,6]. 
Calculusparticle motion
1. A particle is moving on the xaxis (or any number line) Its position x(t), or distance from the origin, at the time t is given by x(t)=4t^316t^2+15t. t is greater than or equal to 0 a.) Where is the particle when it is at rest? 
calculus
The velocity function is v(t) =  t^2 + 4 t  3 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [2,6]. 
Calculus
A particle travels along the xaxis so that its velocity is given by v(t)=cos3x for 0<(or equal to)t<(or equal to)5. When t=0, the particle is at x=5. a. What is the smallest xcoordinate of the particle? 
calculus
5. A particle moves along the y – axis with velocity given by v(t)=tsine(t^2) for t>=0 . a. In which direction (up or down) is the particle moving at time t = 1.5? 
physics,dynamics
The acceleration of a particle along a straight line is defined by a = (2t  9) m/s2, where t is in seconds. At t = 0, s = 1 m and v = 10 m/s. When t = 9 s, determine (a) the particle’s position, (b) the total distance traveled, … 
math
For 4.95 seconds , a particle moves in a straight line according to the position function: s(t) = e^t(5t)5 . a. when id the particle at rest ? 
Calculus (math)
The velocity function (in meters per second) for a particle moving along a line is given by v(t)=t3−5t2. Find the displacement and the distance traveled by the particle during the time interval [1,6]. Distance traveled = ? 
Calculus
The velocity function is v(t)=t^2−5t+4 for a particle moving along a line. Find the displacement and the distance traveled by the particle during the time interval [1,5]. So I found the antiderivative of the function, which gave …