# Chemistry

posted by .

I found the charges on all of the following atoms and found out that Mn was reduced and C was oxidized.

CH3OH- + MnO4- ----> Mn2+ + CH2O
2e-/C 5e-/Mn
x 5 x 2
= 10 = 10

5CH3OH- + 2MnO4- ----> Mn2+ + CH2O

Can anyone help me balance the rest?

• Chemistry -

I don't believe the CH3OH has a charge on it.
6H^+ + 5CH3OH + 2MnO4^- ==>2Mn^+2 + 5CH2O + 8H2O. Check it to make sure it balances BOTH with atoms and charge.

• Chemistry -

Oh no..it doesn't. I misread it because of the print. Wouldn't that change the whole thing? I don't think it would have a coefficient of 5 anymore. I'm balancing redox equations. And now since the overall charge has changed, the charge on the carbon has changed, and so the oxidation has changed.

• Chemistry -

You are right and no, you're not right. Sound confusing?
I balanced the equation as if the negative charge on the CH3OH was NOT there so my equation is correct, I think. You are right that a negative charge there, or is one WAS there and you took it off, it would change the oxidation states; however, C would still be oxidized and Mn still is reduced. Here is the way you do those redox equations.
Mn goes from +7 on the left to +2 on the right. That is a gaiin of 5 electrons and it is reduced.
C on the left, in CH3OH, has an oxidation state of -2. It goes to 0 on the right in CH2O. That is a loss of 2 elecrons which makes C oxidized. 10 is the lowest common multiple, so multiply Mn by 5 and CH3OH by 2 which gets 10 elecrons gained and 10 electrons lost. Now add water to the right side to balance the O atoms, then add H ion on the left to balance H atoms. Then check to make sure the charge balances. I just check it one more time and all atoms balance. All charges balance.

• Chemistry -

Check that. I made a big typo. The manganese half equation is multiplied by 2 and the CH3OH/CH2O half equation is multiplied by 5. The equation is wrote is balanced, both with atoms and with charge but I mistyped the coefficients in the explanation.

## Similar Questions

1. ### Chemistry - DrBob222

CH3OH + MnO4- ----> Mn2+ + CH2O Earlier I posted this question and then realized that CH3OH didn't have a charge. It changed my work because the oxidation state changed. Can you check if what I fixed is correct?
2. ### Chemistry

For the following electrochemical cell: Fe(s)/Fe2+(aq)//MnO4–(aq), Mn2+(aq)/ Pt(s) Which letter corresponds to the correct balanced chemical equation in an acidic solution?
3. ### Chemistry

For the following electrochemical cell: Fe(s) | Fe2+(aq) || MnO4–(aq), Mn2+(aq) | Pt(s) Which letter corresponds to the correct balanced chemical equation in an acidic solution?
4. ### Chemistry

For the following electrochemical cell: Fe(s) / Fe2+(aq) // MnO4–(aq) Mn2+(aq) / Pt(s) Which letter corresponds to the correct balanced chemical equation in an acidic solution?
5. ### Chemistry

For the following electrochemical cell: Fe(s) / Fe2+(aq) // MnO4–(aq) Mn2+(aq) / Pt(s) Which letter corresponds to the correct balanced chemical equation in an acidic solution?
6. ### Chemistry

What is the reduction half-reaction for the reaction between iron(II) sulfate and potassium permanganate in a sulfuric acid solution?
7. ### chemistry

permanganate ion oxidizes hydrogen peroxide to oxygen gas and Mn2+ in acidic solution balance this equation: MnO4- + H2O2 yield Mn2+ + O2 this is what i got 16H+ + 2MnO4- + 5H2O2 yield 2Mn2+ + 8H2O + 5O2 + 10H+ all the atoms and charges …
8. ### chemistry

what is the oxidation half reaction, reduction half reaction, and the complete balanced reaction of the following?
9. ### chemistry Dr BOB

In many residential water systems, the aqueous Fe3+ concentration is high enough to stain sinks and turn drinking water light brown. The iron content is analyzed by first reducing the Fe3+ to Fe2+ and then titrating with MnO4- in acidic …
10. ### Quantitative Chemistry

Which of the following statements about the reaction, 4 HCl(aq) + MnO2(s) MnCl2(aq) + 2 H2O(l) + 2 Cl2(g), is correct?

More Similar Questions