# calculus

posted by
**Anonymous**
.

evaluate integral or state that it is diverges

integral -oo, -2 [2/(x^2-1)] dx

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integral -oo, -2 [2/(x^2-1)] dx

Through partial fractions, I came up with lim [ln(x-1)-ln(x+1)] b, -2

b->-oo

I get (ln(3)-0)-(oo-oo)). The answer in the back of the book is ln(3). What am I doing wrong?