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Find the equation of the tangent line
5x^2+y^2=14 at (1,3).
P.S: It's calculus.

So far I know this much
-10x -10x
2y(dy/dx)= -10x
(dy/dx)= -10x/2y= -5x/y
m= -5(1)/3= -5/3
3= -5/3(1)+b then what?

  • Math -

    ahh, so close!

    solve for b in your last equation
    I get b = 14/3

    put m and b into your y = mx + b and you are done

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