Math
posted by Skye .
Find the equation of the tangent line
5x^2+y^2=14 at (1,3).
P.S: It's calculus.
So far I know this much
10x+2y(dy/dx)=o
10x 10x
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2y(dy/dx)= 10x
(dy/dx)= 10x/2y= 5x/y
m= 5(1)/3= 5/3
y=mx+b
3= 5/3(1)+b then what?

ahh, so close!
solve for b in your last equation
I get b = 14/3
put m and b into your y = mx + b and you are done