Post a New Question

physical science

posted by .

a player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds.

how much force was exerted on the puck?

how much force did the puck exert on the hockey stick?

  • physical science -

    Force = rate of change of momentum (in other words m (delta v/ delta t) or m a)
    F = m (change in velocity/change in time)
    F = .2 (6/2) = .6 Newtons average during the 2 seconds.
    Another way, which is really the same, is to say Force * time = impulse which is mass times change in velocity
    F * 2 = .2 (6)
    F = .6 Newtons again

    Newton's third law says same force, .6 Newtons exerted back on the stick by the puck

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question