physical science
posted by lisa .
a player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds.
how much force was exerted on the puck?
how much force did the puck exert on the hockey stick?

Force = rate of change of momentum (in other words m (delta v/ delta t) or m a)
F = m (change in velocity/change in time)
F = .2 (6/2) = .6 Newtons average during the 2 seconds.
Another way, which is really the same, is to say Force * time = impulse which is mass times change in velocity
F * 2 = .2 (6)
F = .6 Newtons again
Newton's third law says same force, .6 Newtons exerted back on the stick by the puck