precal
posted by Kelly .
can anyone please explain to me how to simplify this exponential expression??I got no idea...THANKS A LOT!
[(8x^6)/(y^6)]^2/3

precal 
Damon
(8 x^6 y^6)^2/3
square everything to get rid of that pesky  sign
(64 x^12 y^12 )^1/3
now take the cube roots
4 x^4 y^4
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