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Physics

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How do you use this equation?

mgh+1/2mvh=mgh+1/2mv^2+Fd

  • Physics -

    How you use it depends upon the problem you are trying to solve.

    It looks like you are trying to use conservation of energy to solve a problem of height and velocity of an object moving in a gravitational field, with a work or drag term (Fd) included. However the mvh on the left would have to be mv^2. Even more important, the v's and h's on the right and left sides shoule have different subscripts, since they would apply to different times along the trajectory.

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