posted by Raj .
I can't figure this one out, the antiderivative of x^-1.
I thought it would be c, but the derivative of c is zero.
That would be the integral of 1/x. It is called the natural logarithm of x, or ln x.
You can't use the rule that the integral of x^n is x^(n+1)/(n+1) on this one, because n = -1 and you get a zero denominator
Integration of 1/x with respect to x is nayural logarithm of x
Integration of 1/x with respect to x is natural logarithm of x