Algebra
posted by Amber .
An airplane traveled 1092 miles with a tailwind, turned around and returned 1092 miles against the same wind to its starting point. The trip with the wind took 6hrs and the return flight against the wind took 8hrs. Find the speed of the plane and the wind.
dealing w/ subst. and elimin.

let the speed of the plane in still air be x mph
let the speed of the wind by y mph
6(x+y) = 1092
8(xy) = 1092
divide the first equation by 6, then second by 8, then add them
looks quite easy
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