a box contains 63 marbles 21 brown, 21 purple and 21 while what is the probability of picking a purple marble on the 1st attempt anor a brown marble on the second attempt?
purple- 1 in 63
brown- 1 in 62
purple- 21/63 reduced to 1/3
brown- 21/62
purple- 1/3
brown 21/62
the probability of picking the 2 marbles the way you described it is
21/63 * 21/62
To find the probability of picking a purple marble on the first attempt and a brown marble on the second attempt, we need to calculate the probability of each event separately and then multiply them together.
Given:
Total number of marbles = 63
Number of purple marbles = 21
Number of brown marbles = 21
Number of white marbles = 21
1. Probability of picking a purple marble on the first attempt:
The probability of picking a purple marble on the first attempt is equal to the number of favorable outcomes (number of purple marbles) divided by the total number of outcomes (total number of marbles). Therefore, the probability is 21/63 = 1/3.
2. Probability of picking a brown marble on the second attempt:
Once a marble has been picked on the first attempt, there will be a total of 62 remaining marbles, with 20 brown marbles. So, the probability of picking a brown marble on the second attempt is 20/62 = 10/31.
To find the combined probability, we multiply the probabilities of the individual events:
Probability of picking a purple marble on the first attempt * Probability of picking a brown marble on the second attempt = (1/3) * (10/31) = 10/93.
Therefore, the probability of picking a purple marble on the first attempt and a brown marble on the second attempt is 10/93.