# Algebra 1

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The ordered pairs in each exercise are for the same direct variation.
Find the missing value.

(3,2) and (6,y)

I don't know how to find the missing value ..

• Algebra 1 -

Assuming that "direct variation" means that the second number of each pair is a certain fixed ratio to the first number, then
3/2 = 6/y
3y = 12
y = ?

• Algebra 1 -

y=4?

• Algebra 1 -

yes, 4

• Algebra 1 -

well.....yes 4 but what if it was

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