Statistics

posted by .

Use a chi-squared test to test the claim about the population variance or standard deviation at the given level of significance and using the given sample statistics.

Claim: ơ2 ≤ 60; α = 0.025. Sample statistics: s2 = 72.7, n = 15

  • Statistics -

    You might try this formula for your chi-square test:

    Chi-square = (n - 1)(sample variance)/(value specified in the null hypothesis)

    n = 15
    sample variance = 72.7
    value specified in the null hypothesis = 60

    Chi-square = (15 - 1)(72.7)/60

    Finish the calculation for your chi-square test statistic.

    Degrees of freedom is equal to n - 1, which is 14.

    Check a chi-square distribution table using alpha = 0.025, with 14 degrees of freedom to determine your critical or cutoff value.

    If the test statistic does not exceed the critical or cutoff value from the table, then the null is not rejected. If the test statistic exceeds the critical or cutoff value from the table, then the null is rejected.

    I hope this will help.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Statistics

    Use a x squared-test to test the claim about the population variance or standard deviation at the given level of significance and using the given sample statistics. Claim: ơ2 ≤ 60; α = 0.025. Sample statistics: s2 = …
  2. statistics

    Prep Courses? Scores for men (nationwide) on the verbal portion of the SAT test are normally distributed with a mean of 509 and a standard deviation of 112. Randomly selected men are given the Columbia review course before taking the
  3. statistics

    Given a sample size of 38, with sample mean 660.3 and sample standard deviation 95.9 we are to perform the following hypothesis test. Null Hypothesis H0: ƒÊ = 700 Alternative Hypothesis H0: ƒÊ ‚ 700 At significance level 0.05 …
  4. Statistics

    This is the first question..... For a population that has a standard deviation of 10, figure the standard deviation of the distribution of means for samples of size- (b) 3. This is the second question....For each of the following samples …
  5. statistics

    For each of the following samples that were given an experimental treatment, test whether these samples represent populations that are different from the general population (a) a sample of 10 with a mean of 44, (b) a sample of 1 with …
  6. statistics

    For each of the following samples that were given an experimental treatment, test whether these samples represent populations that are different from the general population: (a) a sample of 10 with a mean of 44, (b) a sample of 1 with …
  7. statistics

    an auditor wishes to test the assumption that the mean value of all accounts receivable in a given firm is $260.00 she will reject this claim only if it is clearly contradicted by the sample mean. the sample standard deviation of 36 …
  8. statistics

    it is stated that the standard deviation sample of the is 7.6 (n = 26). Test the claim to a significance level of 0.10 that the population standard deviation was greater than 7.0. Round all answers to 3 decimal places.
  9. statistics

    it is stated that the standard deviation sample of the is 7.6 (n = 26). Test the claim to a significance level of 0.10 that the population standard deviation was greater than 7.0. Round all answers to 3 decimal places.
  10. statistics

    A random sample of 49 credit ratings is obtained, and it is found that they have a (sample) mean of 679.3 and a sample standard deviation of 95.9. Using a 0.05 level of significance, test the claim that these credit ratings are from …

More Similar Questions