Chemistry
posted by Lucy .
How many joules are needed to heat 8.50 grams of ice from 10.0 degrees C to 25.0 degrees C?

q1 = heat necessary to change ice from 10 to zero = mass x specific heat ice x (Tfinal  Tinitial) where Tfinal is zero and Tinitial is 10.
q2 = heat necessary to melt ice but stay at zero = mass x heat fusion of ice.
q3= heat necessary to heat water at zero to 25 C. = mass x specific heat water x (250).
total = q1 + q2 + q3.
Post your work if you get stuck.
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