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functions math

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hi can any one please help me solve this question?

logbase2x+logbase2 3= 3

i factored the left side but i have no idea what to do with the right side.

  • functions math -

    log_2(3)x + log_2(3) = 3
    log_2(3)x + log_2(3) = log_2(2^3)
    log_2 [(x)(3)] = log_2(8)
    (x)(3) = 8
    x = 8/3


    Log_2 = log base 2
    2^3 = 2 to the power of 3
    (x)(3) = x times 3
    8/3 = 8 over 3

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