college math

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14. (2 pts) How many different ways are there for an admissions officer to select a group of 7 college candidates from a group of 19 applicants for an interview?

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    Now here the order of things in the group does not matter so we want the number of combinations of 7 out of 19
    C(n,r)= n!/[r!(n-r)!]
    = 19!/[7!(12!)]
    =19*18*17*16*15*14*13/(7*6*5*4*3*2)
    =19*3*17*4*1*13/1
    =50,388
    check my arithmetic for sure if you have a calculator that does factorials.

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