what is the square root of x4
If you mean x4, that is
(x4)1/2 = x2
Do you mean of x^4 ?
if so
(x^4)^1/2 = x^(4 *.5) = x^2
prove it to yourself:
sqrt (x*x*x*x) = x*x
thanks
To find the square root of x^4, we can apply the general rule of square root: the square root of (a^2) is equal to a.
Applying this rule to x^4, we get the square root of (x^2 * x^2). By the product rule of radicals, the square root of (a * b) is equal to the square root of a multiplied by the square root of b.
Therefore, the square root of (x^2 * x^2) is equal to (x^2)^(1/2) * (x^2)^(1/2).
We can simplify this by applying the power rule of exponents, which states that (a^m)*(a^n) is equal to a^(m+n). In this case, (x^2)^(1/2) * (x^2)^(1/2) simplifies to (x^(2*(1/2))) * (x^(2*(1/2))).
Using the property of square roots that the square root of a^2 is equal to |a|, where |a| represents the absolute value of a, we know that the square root of x^2 is equal to |x|.
Thus, the square root of (x^4) is equal to (|x|)^2.