posted by Britt .
Find the equation of the line containing (7,11) and parallel to y=6.
Find the equation of the line having x-intercept of 5 and y-intercept of -5.
I know that y=mx+b, b=y-mx, and parallel lines have the same slope
A y = 6 line has zero slope. If it goes through (x,y) =(7, 11), the equation must be y = 11.
For your second question, the line goes through (x,y) = (5,0) and (0,-5). The slope is therefore (-5 -0)/(0 -5) = 1
The equation must be of the form
y = x + b
Plug in the coordinates of either point to solve for b.