college algebra
posted by rodrigo .
Let f denote an odd function and g an odd function. Decide whether the function h(x)=g(x) f(x) is even or odd.

h(x) = f(x)g(x)
f(x) = f(x)
g(x) = g(x) >
f(x)g(x) = f(x)g(x) = h(x)
So:
h(x) = h(x) 
g(x)*f(x) is an even function, since both f and g change signs when x is replaced by x