how do you write the equilibrium expression for: C3H8 + SO2-><- 3CO2 + 4H2O?
how do you write the equilibrium expression for:
C3H8 + 5O2-><- 3CO2 + 4H2O
Keq = (CO2)3(H2O)4/(C3H8)(O2)2.
I am assuming, since this is a combustion reaction, that the H2O is present as a gas. If it isn't, sometimes the water doesn't enter into the equilibrium OR it is essentially constant, in which case it is often omitted from the expression.