# calculus

posted by kelly

Solve the system by the method of your choice. Identify systems with no solutions and systems with infinitely many solutions, using set notation to express their solutions:
x + y = 3
-2 + y = -3

(0 ,-5)
(0 , 0)
(-2 ,-1)
(-2,-3)

1. kelly

x + y = 3 should be - 3

2. drwls

If -2+y = -3, then y = -1
If also x+y = -3, then
x-1 = -3 and x = -2

3. Kelly

thanks that's what I had I just wasn't sure if -2 + y = -3 (-2,-1) if I multipied -2(-2, -1)

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