# math

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Write m^p = q using logarithms.

Solve (1/e)^2x = 14

• math -

by definition m^p = q is the same as

logm q = p

for your second question

(1/e)^2x = 14

e^(-2x) = 14
-2x = ln 14
x = -1/2 ln 14

Are you not familiar with the basic properties of logs and exponents?
These type of questions require you to know those.

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