posted by Scott .
Please help me solve the following. Thanks,
Write m^p = q using logarithms.
Solve (1/e)^2x = 14
by definition m^p = q is the same as
logm q = p
for your second question
(1/e)^2x = 14
e^(-2x) = 14
-2x = ln 14
x = -1/2 ln 14
Are you not familiar with the basic properties of logs and exponents?
These type of questions require you to know those.