Calculus
posted by Anonymous .
An equation of the line tangent to the graph of y=(2x+3)/(3x2) at the point (1,5) is...do I take the derivative of y=(2x+3)/(3x2) to find the slope and then plug that into y5=m(x1)?

yes

I took the derivative and got 10/(3x2)^2. So...I plug in 1 in the x. Then, I get the slope to be 10. Finally I plug it in (1,5) and m=10 to get y=10x+15. Is that correct?

check your derivative
I had y' = 13/(3x2^2
so the slope would be 13 
How??????

I don't know. Why are you asking me?

I believe the answer is y = 13x + 18. In the question I had, one of the choices was 13x + y = 18, which is what y = 13x + 18 equals. I got 13 for slope, then plugged it in to get y 5 = 13x + 13

Y=13+18
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