Post a New Question


posted by .

a 15000N car on a hydrolyic lift rests on a cylinder with a piston of radius 0.20M,. if a connecting cylinder with a piston of 0.04M radius is driven by compressed air, what force must be applied to the smaller piston in order to lift the car?

am i doing this right?
(0.04M / 0.20M)* 15000N = 3000N
is this right, if not how do i go about getting the right anwser?

  • physics -

    It is not right. The force required is proportional to the piston area, not the radius.
    15000/(0.2)^2 = F/(0.04)^2
    F = (1/5)^2 * 15,000 = 600 N

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question