Give the full set of quantum numbers for the electron lost when a Cs atom ionizes.
a. n = 6; l = 1; ml = –1; ms = +½
b. n = 5; l = 0; ml = +1; ms = –½
c. n = 5; l = 0; ml = 0; ms = –½
d. n = 6; l = 0; ml = 0; ms = +½
Is the answer A.
The electron LOST is a free electron. leaving a Cs+ ion with a filled-shell Xenon configuration behind.
n = 5 and l=0 ( a 1S spectroscopic state)
The ground state for the Cs+ ion (not the electron) would be n = 5; l = 0; ml = 0 BUT there would be no net electron spin, and 0 ms
I do not agree with the choices. The problem is poorly and confusingly worded
it’s d
No, the answer is not A.
Yes, the answer is A.
To determine the full set of quantum numbers for the electron lost when a Cs atom ionizes, we need to consider the following quantum numbers:
a. Principal quantum number (n): This quantum number describes the energy level of the electron. In this case, it is given as n = 6.
b. Azimuthal quantum number (l): This quantum number determines the shape of the electron's orbital. It can have values ranging from 0 to (n-1). Here, it is given as l = 1.
c. Magnetic quantum number (ml): This quantum number specifies the orientation of the orbital in space. Its values can range from -l to +l. In this case, it is given as ml = -1.
d. Spin quantum number (ms): This quantum number represents the spin direction of the electron. It can have two values: +½ for "spin-up" and -½ for "spin-down." Here, it is given as ms = +½.
Thus, the full set of quantum numbers for the electron lost when a Cs atom ionizes is: n = 6; l = 1; ml = -1; ms = +½.