Physics repost
posted by Lindsay .
A regulation volleyball court is L = 18.0 m long and a regulation volleyball net is d = 2.43 m high. A volleyball player strikes the ball a height h = 1.76 m directly above the back line, and the ball's initial velocity makes an angle q = 55° with respect to the ground. At what initial speed must the ball be hit so that it lands directly on the opponent's back line?
Would my equation for the xdir. be Vcos 55*T = 18, since it's the full length of the court?
What would my height for the ydir. be? Vsin 55*T  (g/2)T^2 = ???

<<Would my equation for the xdir. be Vcos55*T = 18, since it's the full length of the court?
YES VT = 31.38 m
<<What would my height for the ydir. be?>>
Vsin55*T  (g/2)T^2 = 1.76
sin55*31.38  4.9 T^2 = 1.76
25.71 + 1.76 = 4.9 T^2
T = 2.37 s
V = 13.2 m/s
After you get V by solving the two simultaneous equations, make sure that the net is also cleared by calculating the height at which it passes by the net.
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