Math Corrections
posted by Chris .
(9)4w+7w=42
I thought I knew how to do this, but my teacher said i was wrong. This what I thought:
(9)4w+7w=42
(9)11w=42
+11w +11w
(9)=42+11w
42 42
(9)42
(9)+(42)
11w=(51)
/11 /11
w= 4.636363636363......
She told us that the correct answer is 17, but I could not find any way 17 could be the answer. Please help me with this and show me the correct way to do this.
Thank you so much.

(9)4w+7w=42
(9)11w=42 4w+7w = +3w. You don't change the sign of the 7w unless you move it to the other side.
+11w +11w
(9)=42+11w
42 42
(9)42
(9)+(42)
11w=(51)
/11 /11
w= 4.636363636363......
The answer is, indeed, 17. 
(9)4w+7w=42
(9)(4)+7w=42
(9)3w=42
+3w +3w
(9)=42+3w
42 42
(9)42
(9)+(42)
3w= 51
/3w /3w
w= 17
I got 17. How is this possible? 
Reread my first response.
4w+7w= +3w and not 3w. 
I know that it was positive. I wrote a minus sign, not a negative sign. What do I have to do.
P.S Sorry, but I really want to get it right. 
No, you wrote a 3w where I have placed the asterisks. You made another error also, You placed a  sign in front of a 4. You should not have done that.I have placed a # mark there.
(9)4w+7w=42
(9)##(4)+7w=42
(9)3w***=42
+3w +3w
(9)=42+3w
42 42
(9)42
(9)+(42)
(9)4w+7w=42
9+3w=42
9+9+3w=42+9
3w=51
3w/3 = 51/3
w=17
3w= 51
/3w /3w
w= 17 
Oh, okay I understand now.
Thank you. I did the correct work.
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