# Algerbra

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I have put together the math in words, please help me show the work in a math format. Info below

To find the population growth rate subtract the population of 2006 from 2007. Divide that answer by the 2006 population.

Australia’s growth rate from 2006 to 2007 was 0.67% per year.

1). 20,743,300 subtract 20,605,500 divided by 20,605,500 which equal the Population growth which is .00668 = 0.67%

2). 20,743,300 times .0067 equals the amount of growth of the population in 2007 which equals 138981

3). Find the approximate population which is 138981 + population of 2007 (which is 20,743,300) = 2008 population which is 20,882,281( 26 January 2008)

Using Australia data in the reference

20,882,281( 26 January 2008)

20,743,300 (26 January 2007)
20,605,500 (26 January 2006)
20,171,300 (26 January 2005)

• Algerbra -

It isn't clear what data you are given and what you are asked to calculate. It appears that you took the growth rate from Jan 2006 to 227, and assumed the same to predict the population rate in 2008.
2007 growth rate
= (20,743,300-20,605,500)/20,605,500
= 0.669%

2008 population = (20,743,300)(1.00669) = 20,882,100

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